Q. Acceleration due to gravity is $g$ on the surface of the earth. Then the value of the acceleration due to gravity at a height of 32 km above earth’s surface is (Assume radius of earth to be 6400 km)
A) $0.99\ g$
B) $0.8\ g$
C) $1.01\ g$
D) $0.9\ g$
Explanation
(a) Acceleration due to gravity at height $h$ is
$g^{'} = \frac{g}{\left( 1 + \frac{h}{R_{e}} \right)^{2}} = \frac{g}{\left( 1 + \frac{32}{6400} \right)^{2}} = 0.99\ g$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.