Q. What will be the acceleration due to gravity at height $h$ if $h > \ > R$. Where $R$ is radius of earth and $g$ is acceleration due to gravity on the surface of earth
A) $\frac{g}{\left( 1 + \frac{h}{R} \right)^{2}}$
B) $g\left( 1 - \frac{2h}{R} \right)$
C) $\frac{g}{\left( 1 - \frac{h}{R} \right)^{2}}$
D) $g\left( 1 - \frac{h}{R} \right)$
Explanation
(a) $g^{'} = g\left( \frac{R}{R + h} \right)^{2} = \frac{g}{\left( 1 + \frac{h}{R} \right)^{2}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.