Q. If the radius of a planet is $R$ and its density is $\rho$, the escape velocity from its surface will be
A) $v_{e} \propto \rho R$
B) $v_{e} \propto \sqrt{\rho R}$
C) $v_{e} \propto \frac{\sqrt{\rho}}{R}$
D) $v_{e} \propto \frac{1}{\sqrt{\rho}R}$
Explanation
(b) $v_{e} = R\sqrt{\frac{8}{3}G\pi\rho}\ \ \therefore v_{e} \propto R\sqrt{\rho}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.