(c) $v_{e} = \sqrt{2gR} \Rightarrow \frac{v_{A}}{v_{B}} = \sqrt{\frac{g_{A}}{g_{B}} \times \frac{R_{A}}{R_{B}}} = \sqrt{x \times r}\therefore\frac{v_{A}}{v_{B}} = \sqrt{rx}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.