Q. Escape velocity on a planet is $v_{e}$. If radius of the planet remains same and mass becomes 4 times, the escape velocity becomes
A) $4v_{e}$
B) $2v_{e}$
C) $v_{e}$
D) $\frac{1}{2}v_{e}$
Explanation
(b) $v_{e} = \sqrt{\frac{2GM}{R}} \Rightarrow v_{e} \propto \sqrt{M}$ if $R =$ constant
If the mass of the planet becomes four times then escape velocity will become 2 times
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.