Q. Two bodies of masses 100 kg and 1000 kg are separated by distance of 1 m. What is the intensity of gravitational field at the mid point of the line joining them?
A) $6.6 \times 10^{- 11}Nm^{2}kg^{- 2}$
B) $2.4 \times 10^{- 8}Mkg^{- 1}$
C) $2.4 \times 10^{- 7}Nkg^{- 1}$
D) $2.4 \times 10^{- 6}Nkg^{- 1}$
Explanation
(c) Resultant gravitational intensity at a mid-point on the line joining the two bodies is
$I = \frac{Gm_{2}}{(r/2)^{2}\ }–\frac{Gm_{1}}{(r/2)^{2}\ } = \frac{4G}{r^{2}}(m_{2} - m_{1})$
$= \frac{4 \times 6.6 \times 10^{- 11}}{1^{2}}(1000 - 100)$
$= 2.4 \times 10^{- 7}Mkg^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.