Q. If the mass of moon is$\frac{1}{90}\ $of earth^' s mass, its radius is$\frac{1}{3}\ $of earth^' sradius and if g is$\ $ acceleration due to gravity on earth, then the acceleration due to gravity on moon is..
A) $\frac{g}{3}$
B) $\frac{g}{90}$
C) $\frac{g}{10}$
D) $\frac{g}{9}$
Explanation
(c) $Acceleration\ due\ to\ gravity\ on\ moon\ g_{m} = \frac{G \times M/90}{{(R/3)}^{2}} = \frac{1}{10}g$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.