Q. The orbital speed of an artificial satellite very close to the surface of the earth is $V_{o}$. Then the orbital speed of another artificial satellite at a height equal to three times the radius of the earth is
A) $1\ V_{o}$
B) $2\ V_{o}$
C) $0.5\ V_{o}$
D) $4\ V_{o}$
Explanation
(c) $v \propto \frac{1}{\sqrt{r}}$, If $r = R$ then $v = V_{0}$
If $r = R + h = R + 3R = 4R$ then $v = \frac{V_{0}}{2} = 0.5V_{0}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.