Q. An artificial of mass $'m'$ revolves around the earth near to its surface then its binding energy is [$R_{e},g$ are radius and acceleration due to gravity respectively of the earth]
A) $\frac{1}{2}mg\ R_{e}$
B) $- \frac{1}{2}mg\ R_{e}$
C) $mg\ R_{e}$
D) $- mg\ R_{e}$
Explanation
(a) Binding energy $= |E|$
$= \frac{1}{2}\frac{GMm}{R_{e}} = \frac{1}{2}gmR_{e}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.