Q. The acceleration due to gravity near the surface of a planet of radius $R$ and density d is proportional to
A) $\frac{d}{R^{2}}$
B) $dR^{2}$
C) $dR$
D) $\frac{d}{R}$
Explanation
(c) $g = \frac{4}{3}\pi\rho GR \Rightarrow g \propto dR$ $(\rho = d$ given in the problem)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.