Q. Two satellite $A$ and $B$, ratio of masses 3 : 1 are in circular orbits of radii $r$ and $4r$. Then ratio of total mechanical energy of $A$ to $B$ is

A) 1 : 3
B) 3 : 1
C) 3 : 4
D) 12 : 1
Explanation

(d) Total mechanical energy of satellite
$E = \frac{- GMm}{2r} \Rightarrow \frac{E_{A}}{E_{B}} = \frac{m_{A}}{m_{B}} \times \frac{r_{B}}{r_{A}} \Rightarrow \frac{3}{1} \times \frac{4r}{r} = \frac{12}{1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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