(c) $v_{0} = \sqrt{\frac{GM}{r}} = \sqrt{\frac{gR^{2}}{r}} = \sqrt{\frac{10 \times \left( 64 \times 10^{5} \right)^{2}}{8000 \times 10^{3}}}$ $= 71.5 \times 10^{2}m/s = 7.15\ km/s$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.