Q. Two identical satellite $A$ and $B$ are circulating round the earth at the height of $R$ and $2R$ respectively. (where $R$ is radius of the earth). The ratio of kinetic energy of $A$ to that of $B$ is

A) $\frac{1}{2}$
B) $\frac{2}{3}$
C) 2
D) $\frac{3}{2}$
Explanation

(d) $\frac{K_{A}}{K_{B}} = \frac{r_{B}}{r_{A}} = \left( \frac{R + h_{B}}{R + h_{A}} \right) = \left( \frac{R + 2R}{R + R} \right) = \frac{3}{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Gravitation MCQs