The escape velocity of a body on the surface of the earth is $11.2\ km/s$. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become

Question

Dr. Abubacker · Accepted Answer

(c) $v_{e} = \sqrt{\frac{2GM}{R}}\ 	herefore v_{e} \propto \sqrt{\frac{M}{R}}$
If $M$ becomes double and $R$ becomes half then escape velocity becomes two times

Q. The escape velocity of a body on the surface of the earth is $11.2\ km/s$. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become

Explanation

Reviewed by Dr. Abubacker

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