When a force is applied on a wire of uniform cross sectional area $3 imes 10^{- 6}m^{2}$ and length 4m, the increase in length is 1 mm. Energy stored in it will be $\left( \ Y = 2\ imes 10^{11} ight)Nm^{- 2})$

Question

When a force is applied on a wire of uniform cross sectional area $3 	imes 10^{- 6}m^{2}$ and length 4m, the increase in length is 1 mm. Energy stored in it will be $\left( \ Y = 2\ 	imes 10^{11} ight)Nm^{- 2})$

Dr. Abubacker · Accepted Answer

(c) Energy $U = \frac{1}{2}\  	imes \frac{4Al^{2}}{L}\ $
=$\frac{1}{2}\  	imes \ \frac{2 	imes 10^{11} 	imes 3 	imes 10^{- 6} 	imes \left( 1 	imes 10^{- 3} ight)^{2}}{4}$
= 0.075 J

Q. When a force is applied on a wire of uniform cross sectional area $3 \times 10^{- 6}m^{2}$ and length 4m, the increase in length is 1 mm. Energy stored in it will be $\left( \ Y = 2\ \times 10^{11} \right)Nm^{- 2})$

Explanation

Reviewed by Dr. Abubacker

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