Q. Longitudinal stress of $1\ N/mm^{2}$ is applied on a wire. The percentage increase in length is $(Y = 10^{11}N/m^{2})$
A) 0.002
B) 0.001
C) 0.003
D) 0.01
Explanation
(b) Longitudinal strain $\frac{l}{L} = \frac{stress}{Y} = \frac{10^{6}}{10^{11}} = 10^{- 5}$
Percentage increase in length $= 10^{- 5} \times 100 = 0.001\%$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.