Q. The relation between $\gamma,\eta$ and $K$ for a elastic material is
A) $\frac{1}{\eta} = \frac{1}{3\gamma} + \frac{1}{9K}$
B) $\frac{1}{K} = \frac{1}{3\gamma} + \frac{1}{9\eta}$
C) $\frac{1}{\gamma} = \frac{1}{3K} + \frac{1}{9\eta}$
D) $\frac{1}{\gamma} = \frac{1}{3\eta} + \frac{1}{9K}$
Explanation
The correct answer is Option D: $\frac{1}{\gamma} = \frac{1}{3\eta} + \frac{1}{9K}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.