A steel wire of 1m long and $1mm^{2}$ cross section area is hang from rigid end. When weight of $1kg$ is hung from it then change in length will be (given $Y = 2 imes 10^{11}N/m^{2}$)

Question

A steel wire of 1m long and $1mm^{2}$ cross section area is hang from rigid end. When weight of $1kg$ is hung from it then change in length will be (given $Y = 2 	imes 10^{11}N/m^{2}$)

Dr. Abubacker · Accepted Answer

(c) $l = \frac{MgL}{YA} = \frac{1 	imes 10 	imes 1}{2 	imes 10^{11} 	imes 10^{- 6}} = 0.05\ mm$

Q. A steel wire of 1m long and $1mm^{2}$ cross section area is hang from rigid end. When weight of $1kg$ is hung from it then change in length will be (given $Y = 2 \times 10^{11}N/m^{2}$)

Explanation

Reviewed by Dr. Abubacker

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