Q. Bulk modulus of water is $2 \times 10^{9}\ Nm^{- 2}.$ The change in pressure required to increase the density of water by 0.1% is
A) $2\ \times 10^{9}\ Nm^{- 2}$
B) $2\ \times 10^{8}\ Nm^{- 2}$
C) $2\ \times 10^{6}\ Nm^{- 2}$
D) $2\ \times 10^{4}\ Nm^{- 2}$
Explanation
(c) The density would increase by 0.1% if the volume decrease by 0.1%
$K = \ \frac{\mathrm{\Delta}p}{\mathrm{\Delta}V/V}$
$\mathrm{\Delta}V = K\frac{\mathrm{\Delta}V}{V} = 2 \times 10^{9}\ \times \ \frac{0.1}{100} = 2 \times 10^{6}\ Nm^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.