Q. The upper end of a wire of radius 4 mm and length 100 cm is clamped and its other end is twisted through and angle of $30{^\circ}.$ Then angle of shear is
A) 0.012${^\circ}$
B) $0.12{^\circ}$
C) $1.2{^\circ}$
D) $12{^\circ}$
Explanation
(b) Angle of shear $\phi = \frac{r}{l}\theta = \frac{0.4}{100}\ \times 30 = 0.12{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.