Q. Two wires $A$ and $B$ of same length, same area of cross-section having the same Young’s modulus are heated to the same range of temperature. If the coefficient of linear expansion of $A$ is $3/2$ times of that of wire $B$. The ratio of the forces produced in two wires will be

A) 2/3
B) 9/4
C) 4/9
D) 3/2
Explanation

(d) $F = YA\alpha\mathrm{\Delta}\theta$
If $Y,A$ and $\mathrm{\Delta}\theta$ are constant then $\frac{F_{A}}{F_{B}} = \frac{\alpha_{A}}{\alpha_{B}} = \frac{3}{2}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.