Q. Calculate the work done, if a wire is loaded by $'Mg'$ weight and the increase in length is $'l'$
A) $Mgl$
B) Zero
C) $Mgl/2$
D) $2Mgl$
Explanation
(c) Work done $= \frac{1}{2}Fl = \frac{Mgl}{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.