Q. A rod elongated by $l$ when a body of mass M is suspended from it. The work done is
A) $Mgl$
B) $\frac{1}{2}Mgl$
C) $2\ Mgl$
D) zero
Explanation
(b) Work done = $\frac{1}{2}F \times \mathrm{\Delta}l = \frac{1}{2}\ Mgl$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.