Q. The value of force constant between the applied elastic force $F$ and displacement will be
A) $\sqrt{3}$
B) $\frac{1}{\sqrt{3}}$
C) $\frac{1}{2}$
D) $\frac{\sqrt{3}}{2}$
Explanation
(b) Force constant, K $= \tan{30{^\circ} = 1/\sqrt{3}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.