Q. The upper end of a wire of radius 4 mm length 100 cm is clamped and its other end is twisted through an angle of 30${^\circ}$. Then angle of shear is
A) 12${^\circ}$
B) 0.12${^\circ}$
C) 1.2${^\circ}$
D) 0.012${^\circ}$
Explanation
(b) As $\pi\theta = l\phi;so\ \phi = \ \frac{0.4\ \times 30{^\circ}}{100} = 0.12{^\circ}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.