Q. A rectangular block of size $10cm \times 8cm \times 5cm$ is kept in three different positions $P,Q$ and $R$ in turn as shown in the figure. In each case, the shaded area is rigidly fixed and a definite force $F$ is applied tangentially to the opposite face to deform the block. The displacement of the upper face will be

A) Same in all the three cases
B) Maximum in $P$ position
C) Maximum in $Q$ position
D) Maximum in $R$ position
Explanation

(c) $\eta = \frac{F/A}{x/L} \Rightarrow x = \frac{L}{\eta} \times \frac{F}{A}$
If $\eta$ and $F$ are constant then $x \propto \frac{L}{A}$
For maximum displacement area at which force applied should be minimum and vertical side should be maximum, this is given in the $Q$ position of rectangular block

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.