Q. A body of mass $m$ is suspended to an ideal spring of force constant k. The expected change in the position of the body due to an additional force F acting vertically downwards is
A) $\frac{3F}{2k}$
B) $\frac{2F}{k}$
C) $\frac{5F}{2k}$
D) $\frac{4F}{k}$
Explanation
(b) Let the change in position of the body due to additional force is $x.$
So, $F = \frac{1}{2}k\ x$
$\therefore$ $x = \frac{2F}{k}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.