When a weight w is hung from one and of the wire other end being fixed, the elongation produced in it be $l.$ If this wire goes over a pulley and two weights w each are hung at the two ends, the elongation of the wire will be

Question

Dr. Abubacker · Accepted Answer

(c) $Y = \frac{w}{A}\  	imes \frac{L}{l}\ \ or\ \ l = \frac{wL}{YA}$
When wire goes over a pulley and weight w is attached each free ad end of wire, then the tension in the wire is doubled, but the original length of wire is reduced to half, so extension in the wire is
$l^{'} = \ \frac{2w 	imes (L/2)}{YA}$= $\frac{wL}{YA} = l$

Q. When a weight w is hung from one and of the wire other end being fixed, the elongation produced in it be $l.$ If this wire goes over a pulley and two weights w each are hung at the two ends, the elongation of the wire will be

Explanation

Reviewed by Dr. Abubacker

Want more practice?