Q. A cube of side 10 cm is subjected to a tangential force of $5 \times 10^{5}\ N$ at the upper face, keeping lower face fixed. The upper face is displaced by 0.001 radian relative to the lower face along the direction of tangential force. The shear modulus of the material of the cube is
A) $5\ \times 10^{10}\ Nm^{- 2}$
B) $5\ \times 10^{11}\ Nm^{- 2}$
C) $5\ \times 10^{12}\ Nm^{- 2}$
D) $5\ \times 10^{13}\ Nm^{- 2}$
Explanation
(a) $\eta\ = \frac{F}{A\theta} = \ \frac{5\ \times 10^{5}}{100\ \times 10^{- 4} \times 0.001} = 5\ \times 10^{10}{Nm}^{- 2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.