Q. A wire of length L and area of cross-section A is stretched through a certain length $l.$ If Y is Young’s modulus of the material of the wire, then the force constant of the wire is
A) $\frac{YL}{A}$
B) $\frac{Yl}{A}$
C) $\frac{YA}{l}$
D) $\frac{YA}{L}$
Explanation
(d) $Y = \frac{F}{A}\ \times \frac{L}{l}\ \ or\ force\ constant = \frac{F}{l} = \frac{YA}{L}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.