Q. A wire of length L and radius $a$ rigidly fixed at one end. On stretching the other end of the wire with a force F, the increase in its length is $l.$ If another wire of same material but of length 2L and radius $\ 2a$ is stretched with a force 2F, the increase in its length will be

A) $l/4$
B) $l$
C) $l/2$
D) $2l$
Explanation

(b) Young’s modulus $Y = \frac{FL}{Al}$
$= \frac{FL}{{\pi a}^{2}l}$
Since for same material Young’s modulus is same, $ie,$
$Y_{1} = Y_{2}$
or$\ \frac{FL}{\ \ \ \ \ {\pi a}^{2}l} = \frac{(2F)(2L)}{{\pi(2a)}^{2}lʹ}$
or $l^{'} = l$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.