To break a wire, a force of $10^{6}N/m^{2}$ is required. If the density of the material is $3 imes 10^{3}kg/m^{3}$, then the length of the wire which will break by its own weight will be

Question

To break a wire, a force of $10^{6}N/m^{2}$ is required. If the density of the material is $3 	imes 10^{3}kg/m^{3}$, then the length of the wire which will break by its own weight will be

Dr. Abubacker · Accepted Answer

(a) $L = \frac{P}{dg} = \frac{10^{6}}{3 	imes 10^{3} 	imes 10} = \frac{100}{3} = 34m$

Q. To break a wire, a force of $10^{6}N/m^{2}$ is required. If the density of the material is $3 \times 10^{3}kg/m^{3}$, then the length of the wire which will break by its own weight will be

Explanation

Reviewed by Dr. Abubacker

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