Q. A rope 1cm in diameter breaks, if the tension in it exceeds 500 N. The maximum tension that may be given to similar rope of diameter 3 cm is
A) 500 N
B) 3000 N
C) 4500 N
D) 2000 N
Explanation
(c) Breaking stress for both ropes would be same.
$\frac{T_{\max_{1}}}{\pi \times \left( \frac{1}{2} \right)^{2}} = \frac{T_{\max_{2}}}{\pi\left( \frac{3}{2} \right)^{2}}$
${\Longrightarrow T}_{\max_{2}} = 9 \times T_{\max_{2}} = 4500\ N$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.