Q. In the figure three identical springs are shown. From spring A, a mass of 4 kg is hung and spring shows elongation of 1 cm. But when a weight of 6 kg is hung on B, the Hook descends

A) 1 cm
B) 2 cm
C) 3 cm
D) 4 cm
Explanation

(c) $x = \frac{F}{k}\ $
If spring constant is k for the first case, it is $\frac{k}{2}\ $ for second case.
For first case, $1 = \frac{4}{k}$ ………..(i)
For second case, $x^{'} = \ \frac{6}{k/2} = \frac{12}{k}$ ……….(ii)
Dividing Eq. (ii) by Eq. (i), we get
$x^{'} = \ \frac{12/k}{4/k} = 3\ cm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.