(b) $\frac{3}{\eta} + \frac{1}{K} = \frac{9}{Y}$ $\frac{1}{K} = \frac{9}{Y} = \frac{3}{\eta}\ \ \ or\frac{1}{K} = \frac{9}{3\eta} - \frac{3}{\eta} = 0\ \Rightarrow K = \ \infty\ $
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.