(c) As $l = \frac{F}{\pi\left( \frac{d^{2}}{4} \right)} \times \frac{L}{Y}\ so,\ l \propto \frac{L}{d^{2}}$ $\frac{L}{d^{2\ }}\ is\ maximum\ for\ option\ (c).\ $
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.