Q. If the compressibility of water is $\sigma$ per unit atmospheric pressure, then the decrease in volume (V) due to atmospheric pressure $p$ will be
A) $\sigma\ p/V$
B) $\sigma\ pV$
C) $\sigma/pV$
D) $\sigma\ V/p$
Explanation
(b) $K = \frac{p}{\frac{\mathrm{\Delta}V}{V}}\ \ or\frac{1}{K} = \ \frac{\mathrm{\Delta}V/V}{p}$
Or $\sigma = \frac{\mathrm{\Delta}V}{pV}\ \ or\ \mathrm{\Delta}V = \ \sigma pV$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.