Steel and copper wires of same length are stretched by the same weight one after the other. Young’s modulus of steel and copper are $2 imes 10^{11}N/m^{2}$ and $1.2 imes 10^{11}N/m^{2}$. The ratio of increase in length

Question

Steel and copper wires of same length are stretched by the same weight one after the other. Young’s modulus of steel and copper are $2 	imes 10^{11}N/m^{2}$ and $1.2 	imes 10^{11}N/m^{2}$. The ratio of increase in length

Dr. Abubacker · Accepted Answer

(b) $l = \frac{FL}{AY} \Rightarrow \frac{l_{S}}{l_{cu}} = \frac{Y_{cu}}{Y_{S}}\ \lbrack F,L\ and\ Y\ are\ constantbrack$
$	herefore\frac{l_{s}}{l_{cu}} = \frac{1.2 	imes 10^{11}}{2 	imes 10^{11}} = \frac{3}{5}$

Q. Steel and copper wires of same length are stretched by the same weight one after the other. Young’s modulus of steel and copper are $2 \times 10^{11}N/m^{2}$ and $1.2 \times 10^{11}N/m^{2}$. The ratio of increase in length

Explanation

Reviewed by Dr. Abubacker

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