Q. The increase in length on stretching a wire is 0.05%. If its Poisson’s ratio is 0.4, the diameter is reduced by
A) 0.01%
B) 0.02%
C) 0.03%
D) 0.04%
Explanation
(b) $\sigma\ \ = \ \ \frac{Lateral\ strain}{Longitudinal\ strain}$
Or Lateral strain = $\sigma\ \times longitudial\ strain$
= 0.4 $\times \frac{0.5}{100} = \frac{0.02}{100}\ $
So, percentage reduction in diameter is 0.02.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.