Q. If the thickness of the wire is doubled, then the breaking force in the above question will be
A) $6F$
B) $4F$
C) $8F$
D) $F$
Explanation
(b) Breaking force $\propto \pi r^{2}$
If thickness (radius) of wire is doubled then breaking force will become four times
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.