Q. Young’s modulus of the material of a wire is $Y$. On pulling the wire by a force $F$, the increase in its length is $x$. The potential energy of the stretched wire is
A) $\frac{1}{2}Fx$
B) $\frac{1}{2}Yx$
C) $\frac{1}{2}Fx^{2}$
D) None of these
Explanation
(a) When a wire is stretched through a length, then work has to be done, this work is stored in the wire in the form of elastic potential energy
Potential energy of stretched wire is
$U = \frac{1}{2} \times stress \times strain$
$\therefore U = \frac{1}{2} \times F \times s \Rightarrow U = \frac{1}{2}Fx$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.