Q. The temperature of a wire of length 1 m and area of cross section 1 $cm^{2}\ $is increased from$0℃\ \ to\ 100℃$. If the rod is not allowed to increased in length, the force required will be $(\alpha = 10^{- 5}/℃$ and $Y = 10^{11}N/m^{2})$
A) $10^{3}N$
B) $10^{4}N$
C) $10^{5}N$
D) $10^{9}N$
Explanation
(b) $F = force\ developed$
= $YA\ \propto (\mathrm{\Delta}\theta)$
= $10^{11} \times 10^{- 4} \times 10^{- 5} \times 100 = 10^{4}N\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.