Q. The diameter of a brass wire is 0.6 mm and $Y\ $is $9\ \times 10^{6}\ Nm^{- 2}\ .\ $The force which will increase its length by 0.2% is about

A) 100 N
B) 51 N
C) 25 N
D) None of these
Explanation

(b) $F = \frac{YA\mathrm{\Delta}l}{l}\ $
= $9\ \times 10^{10} \times \frac{22}{7} \times \ \frac{\left( 0.6 \times 10^{- 3} \right)^{2}}{4} \times \frac{0.2}{100}N \approx 51\ N$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.