Q. The mean distance between the atoms of iron is $3 \times 10^{- 10}m$ and interatomic force constant for iron is $7N/m$. The Young’s modulus of elasticity for iron is
A) $2.33 \times 10^{5}N/m^{2}$
B) $23.3 \times 10^{10}N/m^{2}$
C) $233 \times 10^{10}N/m^{2}$
D) $2.33 \times 10^{10}N/m^{2}$
Explanation
(d) $Y = \frac{k}{r_{0}} = \frac{7}{3 \times 10^{- 10}} = 2.33 \times 10^{10}N/m^{2}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.