Q. A spring of constant k is cut into parts of length in the ratio 1 : 2. The spring constant of larger on is
A) $\frac{k}{2}$
B) $\frac{k}{3}$
C) $\frac{2k}{3}$
D) $\frac{3k}{2}$
Explanation
(d) $Y = \frac{Fl}{A\mathrm{\Delta}l} = \left( \frac{F}{\mathrm{\Delta}l} \right)\ \frac{1}{A}$ ; $kl = constant;$
$k\ \times 3 = k^{'} \times 2\ \ \ \ or\ k^{'} = \frac{3k}{2}\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.