Q. A $2\ m$ long rod of radius $1\ cm$ which is fixed from one end is given a twist of 0.8 radians. The shear strain developed will be
A) 0.002
B) 0.004
C) 0.008
D) 0.016
Explanation
(b) $r\theta = L\phi \Rightarrow 10^{- 2} \times 0.8 = 2 \times \phi \Rightarrow \phi = 0.004$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.