Q. If Poisson’s ratio $\sigma$ is $- \frac{1}{2}$ for a material, then the material is
A) Uncompressible
B) Elastic fatigue
C) Compressible
D) None of the above
Explanation
(a) $\frac{dV}{V} = (1 + 2\sigma)\frac{dL}{dL}$
If $\sigma = - \frac{1}{2}$ then $\frac{dV}{V} = 0\ i.e.\ K = \infty$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.