(a) $\eta = \ \frac{Y}{2(1 + \sigma)},\ \ \sigma = 0\ $ $\therefore\ \ \eta = \frac{Y}{2} = \ \frac{6\ \times 10^{12}}{2\ } = 3 \times 10^{12}\ {Nm}^{- 2}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.