If a rubber ball is taken at the depth of $200\ m$ in a pool, its volume decreases by 0.1%. If the density of the water is $1 imes 10^{3}kg/m^{3}$ and $g = 10\ m/s^{2}$, then the volume elasticity in $N/m^{2}$ will be

Question

If a rubber ball is taken at the depth of $200\ m$ in a pool, its volume decreases by 0.1%. If the density of the water is $1 	imes 10^{3}kg/m^{3}$ and $g = 10\ m/s^{2}$, then the volume elasticity in $N/m^{2}$ will be

Dr. Abubacker · Accepted Answer

(d) $K = \frac{\mathrm{\Delta}P}{\mathrm{\Delta}V/V} = \frac{hho g}{\mathrm{\Delta}V/V} = \frac{200 	imes 10^{3} 	imes 10}{0.1/100} = 2 	imes 10^{9}$

Q. If a rubber ball is taken at the depth of $200\ m$ in a pool, its volume decreases by 0.1%. If the density of the water is $1 \times 10^{3}kg/m^{3}$ and $g = 10\ m/s^{2}$, then the volume elasticity in $N/m^{2}$ will be

Explanation

Reviewed by Dr. Abubacker

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