Q. The Young’s modulus of a rubber string $8\ cm$ long and density $1.5\ kg/m^{3}$ is $5 \times 10^{8}\ N/m^{2}$, is suspended on the ceiling in a room. The increase in length due to its own weight will be

A) $9.6 \times 10^{- 5}m$
B) $9.6 \times 10^{- 11}m$
C) $9.6 \times 10^{- 3}m$
D) $9.6\ m$
Explanation

(b) $l = \frac{L^{2}dg}{2Y} = \frac{\left( 8 \times 10^{- 2} \right)^{2} \times 1.5 \times 9.8}{2 \times 5 \times 10^{8}} = 9.6 \times 10^{- 11}m$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.